On the left side the denominator of the first fraction is "x" and the denominator of the second fraction is "2". Do they have any factors in common? Since x is a variable so you don't know. You certainly know that "2x" is a "common denominator" and you can't really get least common denominator.
So to get a common denominator multiply numerator and denominator of the first fraction by 2 and multiply numerator and denominator of the second fraction by x to get \(\displaystyle \frac{2}{2x}+ \frac{x}{2x}= \frac{2+ x}{2x}= \frac{11}{6}\).
(I am not including the "6" as Jomo does because I was only concerned with adding the fractions on the left side.)
Now, as for solving that, a pretty standard way to solve "fraction= fraction" is to eliminate the fraction by multiplying both fraction by those denominators. That is, multiply both sides by 6x: \(\displaystyle \frac{2+ x}{2x}(6x)= \frac{11}{6}(6x)\) so \(\displaystyle 3(2+ 2x)= 11x\), \(\displaystyle 6+ 6x= 11x\), \(\displaystyle 6= 5x\).
