#### john458776

##### New member

- Joined
- May 15, 2021

- Messages
- 25

This is how solved it. But I'm not sure if 2.2 is correct.

2.1

\(\displaystyle S\)

_{1}\(\displaystyle = 3\)

\(\displaystyle S\)

_{2}\(\displaystyle = 9/2\)

\(\displaystyle S\)

_{3}\(\displaystyle = 43/9\)

\(\displaystyle S\)

_{4}\(\displaystyle = 39/8\)

\(\displaystyle S\)

_{5}\(\displaystyle = 123/25\)

2.2

\(\displaystyle S\)

_{infinity}\(\displaystyle = 5-2/\)(infinity)

^{2}\(\displaystyle = 5\)

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