what is the weight of the fifth computer?

eddy2017

eddy2017

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the mean weight of five complete computer stations is 167.2 lb.
the wights of four computer stations are 158.4 lb, 162.8 lb, 165 lb, and 178.2 lb respectively.
what is the weight of the fifth computer?

well, I have the mean = 167.2
if I add up the weights of the four stations given =664.4 lb
that is a fact.
mean = (w of station 1 +w of station 2+ w of station 3 + w of station 4 +w of station 5) / number of stations

the w stands for weight
is this set up correct before I input values?. Is this a good way to solve this quickly, using the mean formula?
 
Last edited by a moderator:
eddy2017 said:
the mean weight of five complete computer stations is 167.2 lb.
the wights of four computer stations are 158.4 lb, 162.8 lb, 165 lb, and 178.2 lb respectively.
what is the weight of the fifth computer?

well, I have the mean = 167.2
if I add up the weights of the four stations given =664.4 lb
that is a fact.
[imath]mean = w of station 1 +w of station 2+ w of station 3 + w of station 4 +w of station 5 / number of stations[/imath]

the w stands for weight
is this set up correct before I input values?. Is this a good way to solve this quickly, using the mean formula?
Click to expand...
It would be correct with an appropriate use of parenthesis ;)
 
blamocur said:
It would be correct with an appropriate use of parenthesis ;)
Click to expand...
I put grouping symbols around the numerator. not at the beginning though. you are right. if you look down below I put them when I performed the operation with numbers but not at the presentation of the formula.
 
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there you have it!. my bad. keeps happening to me!.. 191.6!!!!

eddy2017 said:
I put grouping symbols around the numerator.
Click to expand...
not at the beginning, but then I realized I had to.

skeeter said:
check your subtraction …
Click to expand...
it was rather my addition
158.4 + 162.8 =321.2 +165=486.2+178.2= 664.4

THANK YOU FOR EDITING IT!!!

eddy2017 said:
there you have it!. my bad. keeps happening to me!.. 191.6!!!!
Click to expand...
Thanks.

eddy2017 said:
oh, 167.2 = (664.4 + x) / 5
Click to expand...
thanks.
 
eddy2017 said:
836 -664.4 =191.6

what did I do wrong in my operation, skeeter or is not the right method?. the difference in weight is considerable.
Click to expand...

[imath]836-664.4 = 171.6[/imath]

like I said, check your subtraction
 
okay, let me retrace my steps.
158.4 lb, 162.8 lb, 165 lb, and 178.2 I have to add all these four weights.
158.4 + 162.8 + 165+ 178.2=
now,
167.2 =(664+x) / 5
= 171. 6

Sorry, carelessness is going to be my undoing.
 
eddy2017 said:
okay, let me retrace my steps.
158.4 lb, 162.8 lb, 165 lb, and 178.2 I have to add all these four weights.
158.4 + 162.8 + 165+ 178.2=
now,
167.2 =(664+x) / 5
= 171. 6

Sorry, carelessness is going to be my undoing.
Click to expand...
Again you wrote that 167.2 = 171.6. You know that is wrong! Stop writing it!
 
Jomo said:
Again you wrote that 167.2 = 171.6. You know that is wrong! Stop writing it!
Click to expand...
Sorry
(664 + x )/5= 171.6
i dont think there is a need to perform the steps of the calculation, but if you want me to do it, I'll do it.
 
Jomo said:
This just terrible! [math] 158.4 + 162.8 \neq 321.2 + 165[/math][math]321.2 + 165 \neq 486.2 + 178.2[/math]
Click to expand...
NO, YOU'RE NOT SEEING WHAT I DID. I JUST BROKE DOWN THE ADDITION IN TWO PARTS.
 
I did this on my paper
158.4 + 162.8= 321.2
then
321.2+165=486.2
486.2+178.2 =664.4
that was what i did.
 
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