I have the functions
f(x)=sqrt(1-(x-1)^2)
g(x)=sqrt(1-(x-3)^2)
h(x)=sqrt(1-(x-5)^2)
When I add them together to make
f(x)+g(x)+h(x)
and I try to graph it, nothing comes up.
Is this some kind of special ungraphable equation?
The max f(x) g(x) and h(x) can be is 1 because the square root of a negative number is imaginary and won't show on a graph. So you can't subtract anything higher than 1 from 1, and because(x-1) (x-3) and (x-5) are squared, you can never have a negative number that you subtract from 1, therefore adding it.
The lowest it can be is 0 if you have 1-1 under the square root. Then you have to solve for when this is possible. You want what is under the sqrt to be between 0 and 1. So solve for X with these numbers and you get
The max value of X for equation 1 is 2. The min value is 0.
The max value of X for equation 2 is 4. The min value is 2.
The max value of X for equation 3 is 6. The min value is 4.
Equation 1. X is between 0 and 2
Equation 2. X is between 2 and 4
Equation 3. X is between 4 and 6
None of these numbers fit all 3 equations, so one equation will always be undefined. Therefore, it is undefined for all X-Values.