Think your way through it, one step at a time.For certain years from 1950 to 1990, the average annual per capita consumption C of cigaretts by Americans (18 and older) can be modeled by C=3248.89+108.64t-2.98t^2 for 0≤t≤40, where t is the year, with t=0 corresponding to 1950.
a) In 1960, the U.S population (18 and over) was 116,530,000. Of those, about 48,500,000 were smokers. What was the average annual consumption per smoker in 1960? What was the average daily cigarette consumption per smoker?
Formula for Avg Annual per capita consumption
C(t)=3248.89+108.64t-2.98t^2 for 0≤t≤40 and t = 0 means 1950
Total Population
116,530,000
Total Smokers
48,500,000 ==> Almost 42%!!!! But no one asked for that.
"What was the average annual consumption per smoker in 1960?"
Symbolically, we have:
Total Cigs Smoked by Total Population = C(10)*116,530,000
Total Cigs Smoked per smoker = C(10)*116,530,000/48,500,000
"What was the average daily cigarette consumption per smoker?"
(C(10)*116,530,000/48,500,000) / 365
Just put them together as they are requested. No need to try to solve everything at once.