#### abel muroi

##### Junior Member

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^{2}+ bx + c

I mean the other formula with the square root. Btw i don't know how to type the formula here, but I assume you know which formula I'm talking about

- Thread starter abel muroi
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I mean the other formula with the square root. Btw i don't know how to type the formula here, but I assume you know which formula I'm talking about

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Please post a problem - so that we discuss the specifics.^{2}+ bx + c

I mean the other formula with the square root. Btw i don't know how to type the formula here, but I assume you know which formula I'm talking about

We cannot discuss generalities here - you need to ask that in your classroom.

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OK so i was given this problem..Please post a problem - so that we discuss the specifics.

We cannot discuss generalities here - you need to ask that in your classroom.

p(x) = x

can i use the quadratic formula for this problem? even though it doesn't have a third term?

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You are not asking a question. Are you trying to find p(5). If so, then you do not need to use the quadratic equation. If you want to find the y-intercept then you let x=0 and do not use the quadratic formula. If you want to know what happens to p(x) when x is very large you do not use the quadratic formula.OK so i was given this problem..

p(x) = x^{3}- 2x^{2}+ 2x

can i use the quadratic formula for this problem?

In fact you never have to use the quadratic formula.

Also most people would only think about using the quadratic formula when the function is quadratic not cubic.

You seem to have the idea that given a particular function that there is just one thing to do to it so there is no need to ask a question because the question is obvious. Move away from that thinking.

Good luck.

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You are not telling us what did you need to do!! That's what will determine whether you need to use quadratic for this problem - or not. Please be complete!!OK so i was given this problem..

p(x) = x^{4}+ 4x^{2}

can i use the quadratic formula for this problem? even though it doesn't have a third term?

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Abel, all you did was change the function! You still are not asking a question. For the record p(1) = 5 and I did not use the quadratic formula.OK so i was given this problem..

p(x) = x^{4}+ 4x^{2}

can i use the quadratic formula for this problem? even though it doesn't have a third term?

- Joined
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sorry, the problem is asking me to find the complex roots of the function..Abel, all you did was change the function! You still are not asking a question. For the record p(1) = 5 and I did not use the quadratic formula.

but my question is... how can i factor out this function?

I think you mean "the quadratic formula". You can use the quadratic formula for any quadratic equation to find the solutions. The solutions are the x-coordinates of the intersection of the curve with the x-axis. When the curve does not cross the x-axis you get a minus sign inside the square root and you cannot take a minus sign of a square.

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