This is also in regards to this thread:
Jomo was fortunate with his method, because the cube of the left-hand side equals 54.
\(\displaystyle A = \ \sqrt[3]{62} \ \ \ and \ \ \ B = \ 1 + 2\sqrt[3]{3}\)
Without using a calculator or computer, show which is greater, A or B.
Which is greater? A = (3)(2^{1/3}) or B = 1 + (2)(3^{1/3})?
The question is as follows: If A = 3 \cdot 2^{\dfrac{1}{3}}, and B = 1 + 2 \cdot 3^{\dfrac{1}{3}} Which is greater? Answer: Calculator is not accepted on the test. Thanks in advance. :)
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Jomo was fortunate with his method, because the cube of the left-hand side equals 54.
\(\displaystyle A = \ \sqrt[3]{62} \ \ \ and \ \ \ B = \ 1 + 2\sqrt[3]{3}\)
Without using a calculator or computer, show which is greater, A or B.