Yes, I have know a little calculus. My idea is let m in a left side and function of x in the other side, but it's difficult for me to calculate, so I need some hind. Apologise for my English, i don't write it wellDo you know any calculus (such as finding the minimum of this function)?
Please follow the guidelines by showing some work or telling us where you are stuck.
Can you show me the to solve that equation?I tried solving it but it's not workingFind f' (x) and then try to solve f'(x)=0. Please show us your work.
No, you show us your work and we help you arrive at the solution.Can you show me the to solve that equation?I tried solving it but it's not working
i know that f(x)>=0=f(1) so f'(1)=0 and figure out m=2, but i was wondering if m could be a only valueNo, you show us your work and we help you arrive at the solution.
To be honest I am getting tired of looking at your posts and not seeing you show any work. You were told what to do but you refuse to do what we ask. Either answer our questions or go away. Personally I prefer you stay around but you have to play by our rules.i know that f(x)>=0=f(1) so f'(1)=0 and figure out m=2, but i was wondering if m could be a only value
Set that derivative to 0 then bring the square root to the other side and square both sides.f'(x)=8x^3-12x^2+6mx-m-m(2x-1)/sqrt(x^2-x+1), indeed i don't know how to solve this
???? I can't see anythingSet that derivative to 0 then bring the square root to the other side and square both sides.
Let's see where you can go from there.
Assuming your calculation above is correct:f'(x)=8x^3-12x^2+6mx-m-m(2x-1)/sqrt(x^2-x+1), indeed i don't know how to solve this
No, I think It's hard to calculateAssuming your calculation above is correct:
0 = 8x^3 - 12x^2 + 6mx - m - m(2x-1) / sqrt(x^2-x+1)
m * (2x - 1) / sqrt(x^2-x+1) = 8x^3 - 12x^2 + 6mx - m
Now square both sides to eliminate the 'sqrt' part...... and continue....
I have tried it and it's not productiveNo, I think It's hard to calculate
What do you get when you square both sides?Assuming your calculation above is correct:
0 = 8x^3 - 12x^2 + 6mx - m - m(2x-1) / sqrt(x^2-x+1)
m * (2x - 1) / sqrt(x^2-x+1) = 8x^3 - 12x^2 + 6mx - m
Now square both sides to eliminate the 'sqrt' part...... and continue....
uhm m^2(2x-1)^2/(x^2-x+1)=(8x^3-12x^2+6mx-m)^2What do you get when you square both sides?