- Thread starter sufinaz
- Start date

- Joined
- Jun 18, 2007

- Messages
- 21,308

You missed 121,2,3,5,4,6,10,15,,20,30,60 that's all I guess but there is 12 number, is that what it's asking?

- Joined
- Jun 18, 2007

- Messages
- 21,308

No - count again!is the answer 13 than?

- Joined
- Jan 29, 2005

- Messages
- 9,979

No the answer is 12.is the answer 13 than?

Let me give you the general rule:

Write the number in factored form, like \(\displaystyle N=(p_1)^{n_1}\cdot(p_2)^{n_2}\cdot(p_3)^{n_3}\cdots(p_k)^{n_k}\) where each \(\displaystyle p_j\) is a prime factor and each \(\displaystyle n_j\in\mathbb{Z}^+~\&~n_j\ge 1\)

then the number of divisors of \(\displaystyle N\) is \(\displaystyle (n_1+1)\cdot(n_2+1)\cdot(n_3+1)\cdots(n_k+1)\)