pka Elite Member Joined Jan 29, 2005 Messages 11,978 Jan 16, 2017 #1 lookagain said: \(\displaystyle y = x^{\tfrac{1}{3}} \ \ \ and \ \ \ y = \sqrt[3]{x} \ \) are equivalent, but WolframAlpha doesn't handle them the same. Click to expand... See PLOT I PLOT II Do you use WolframAlphaPro? That may be your confusion. Last edited by a moderator: Jan 23, 2017
lookagain said: \(\displaystyle y = x^{\tfrac{1}{3}} \ \ \ and \ \ \ y = \sqrt[3]{x} \ \) are equivalent, but WolframAlpha doesn't handle them the same. Click to expand... See PLOT I PLOT II Do you use WolframAlphaPro? That may be your confusion.
L lookagain Elite Member Joined Aug 22, 2010 Messages 3,249 Jan 16, 2017 #2 The range of y = x^(1/3) for x < 0 is (-oo, 0), and the range of y = x - 4 for x < 0 is also (-oo, 0). Given the product of these, the range of the given function is in Quadrant II. Last edited by a moderator: Jan 23, 2017
The range of y = x^(1/3) for x < 0 is (-oo, 0), and the range of y = x - 4 for x < 0 is also (-oo, 0). Given the product of these, the range of the given function is in Quadrant II.
