- Thread starter lcase
- Start date

rectangular flower bed is 10 ft longer than it's width.

L=W+10

The flower bed is surrounded by a concrete walk that is 3 ft wide.

With the walk it is (L+2*3)by(W+2*3)

The area of the walk is the total area minus the area of the bed.

If the area of the walk is 240, then what is the width of the flower bed

(L+6)(W+6)-(L)(W)=240

Substitute W+10 for L in that last equation then solve for W.

I assume you made a sketch . . .

A rectangular flower bed is 10 ft longer than its width.

The flower bed is surrounded by a concrete walk that is 3 ft wide.

If the area of the walk is 240, then what is the width of the flower bed?

Code:

```
: 3 : w+10 : 3 :
- * - - - - - - - - - *
3 | |
- | * - - - - - * |
| | | |
w | w| | | w+6
| | w+10 | |
- | * - - - - - * |
3 | |
- * - - - - - - - - - *
w+16
```

. . . . . . . . 240 . = . (w + 6)(w + 16) - w(w + 10)

Simplify: . w<sup>2</sup> + 22w + 96 - w<sup>2</sup> - 10w .= .240

Then: . 12w = 144 . . ---> . .