Word problem HELP?

[babyduckee]

How many gallons of 65% antifreeze and how many gallons of 20% antifreeze should be mixed to obtain 50 gallons of a 56% mixture of antifreeze?

 

[skeeter]

let x = amount of 65% antifreeze
50-x = amount of 20% antifreeze

x(.65) + (50-x)(.20) = (50)(.56)

solve for x and 50-x

 

[babyduckee]

so I broke it down after that to:

x(.65)+(50-x)(.20)=28

then:

x(.13)+(50-x)=28

Is this correct so far? If so what should i do next

 

[skeeter]

Is this correct so far?

no.

x(.65) + (50-x)(.20) = (50)(.56)

.65x + 10 - .20x = 28

 

[babyduckee]

ooooh I see. Thank You! I got it from there