J jamiedome New member Joined Sep 16, 2009 Messages 2 Sep 16, 2009 #1 The perimeter of a rectangle is 32m. The length is 10m more than twice the width. Find the dimensions. I am not sure how to get started on this. Please help Thank you, Jamie
The perimeter of a rectangle is 32m. The length is 10m more than twice the width. Find the dimensions. I am not sure how to get started on this. Please help Thank you, Jamie
D Deleted member 4993 Guest Sep 16, 2009 #2 jamiedome said: The perimeter of a rectangle is 32m. The length is 10m more than twice the width. Find the dimensions. I am not sure how to get started on this. Please help Thank you, Jamie Click to expand... Start naming variables Width = W Length = L Perimeter = 2(L+W) = 32
jamiedome said: The perimeter of a rectangle is 32m. The length is 10m more than twice the width. Find the dimensions. I am not sure how to get started on this. Please help Thank you, Jamie Click to expand... Start naming variables Width = W Length = L Perimeter = 2(L+W) = 32
J jamiedome New member Joined Sep 16, 2009 Messages 2 Sep 16, 2009 #3 L=10m+(2W) then how do I find the width?
D Deleted member 4993 Guest Sep 16, 2009 #4 jamiedome said: L=10m+(2W) then how do I find the width? Click to expand... You know 2L + 2W = 32 L + W = 16 Then using the condition you derived: (10 + 2W) + W = 16 Now what......
jamiedome said: L=10m+(2W) then how do I find the width? Click to expand... You know 2L + 2W = 32 L + W = 16 Then using the condition you derived: (10 + 2W) + W = 16 Now what......