bumblebee123
Junior Member
- Joined
- Jan 3, 2018
- Messages
- 200
Hi, I have been working on understanding this question for a few days. I have figured out a bit but am at a loss with the end bit. So, here goes:
Write
(5/4x^2 - 25) - (2x+3) / ((4x^2+16x+15)/7)
as a single fraction in its simplest form.
The answer is :
(40-14x)/(4x^2-25)
I hope I have written it right.
In short, although it's taken me ages to get there, I have
looked at the right-hand side and dealt with division first:
(2x+3) / ((4x^2+16x+15)/7)
to become
7/(2x+5)
I was able to factorize the (4x^2+16x+15) to (2x+5)(2x+3) so that I could then divide the (2x+3) to get rid of it from top and bottom of the fraction to leave 7/(2x+5)
Then I had to deal with subtracting it:
(5/4x^2 - 25)- 7/(2x+5)
But I thought I had to have the denominators the same so I tried multiplying left side with (2x+5) and right side with this 4x^2 - 25 and ended up with
(5(2x+5)-7(4x^2-25))/((2x+5)(4x^2-25))
but its not right.
Any help would be great, thank you in advance.
Write
(5/4x^2 - 25) - (2x+3) / ((4x^2+16x+15)/7)
as a single fraction in its simplest form.
The answer is :
(40-14x)/(4x^2-25)
I hope I have written it right.
In short, although it's taken me ages to get there, I have
looked at the right-hand side and dealt with division first:
(2x+3) / ((4x^2+16x+15)/7)
to become
7/(2x+5)
I was able to factorize the (4x^2+16x+15) to (2x+5)(2x+3) so that I could then divide the (2x+3) to get rid of it from top and bottom of the fraction to leave 7/(2x+5)
Then I had to deal with subtracting it:
(5/4x^2 - 25)- 7/(2x+5)
But I thought I had to have the denominators the same so I tried multiplying left side with (2x+5) and right side with this 4x^2 - 25 and ended up with
(5(2x+5)-7(4x^2-25))/((2x+5)(4x^2-25))
but its not right.
Any help would be great, thank you in advance.