markbrock30
New member
- Joined
- Mar 5, 2008
- Messages
- 23
x" + 2*(3+R)*x' + 3*(3+R)*x = 0
x(0) = 10
the above equation (second order) was derived from:
(dx/dt) = -(3+R)*x + R*y, and
(dy/dt) = (3+R)*x - (3+R)*y
How can I find x'(0)?
I can't replicate the examples in my notes.
Cheers,
Mark.