xy+y/y=???? my answer is xy is this correct?
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mmm4444bot
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Re: xy+y/y=????
No, your answer is not correct.
Let me show you another way to look at your expression.
\(\displaystyle \frac{xy + y}{y} = \frac{xy}{y} + \frac{y}{y}\)
In other words, when you have an algebraic fraction with one term on the bottom and multiple terms on the top, then EACH term on the top is being divided by the single term on the bottom.
\(\displaystyle \frac{A + B}{E} = \frac{A}{E} + \frac{B}{E}\)
\(\displaystyle \frac{A + B + C}{E} = \frac{A}{E} + \frac{B}{E} + \frac{C}{E}\)
This pattern is true even if there is MORE than one term on the bottom.
\(\displaystyle \frac{A + B}{E + F} = \frac{A}{E + F} + \frac{B}{E + F}\)
Does this information help you to simplify your expression? You cannot simply cancel the y on the bottom with one y on the top and say you're done.
My edits: deleted overkill examples
No, your answer is not correct.
Let me show you another way to look at your expression.
\(\displaystyle \frac{xy + y}{y} = \frac{xy}{y} + \frac{y}{y}\)
In other words, when you have an algebraic fraction with one term on the bottom and multiple terms on the top, then EACH term on the top is being divided by the single term on the bottom.
\(\displaystyle \frac{A + B}{E} = \frac{A}{E} + \frac{B}{E}\)
\(\displaystyle \frac{A + B + C}{E} = \frac{A}{E} + \frac{B}{E} + \frac{C}{E}\)
This pattern is true even if there is MORE than one term on the bottom.
\(\displaystyle \frac{A + B}{E + F} = \frac{A}{E + F} + \frac{B}{E + F}\)
Does this information help you to simplify your expression? You cannot simply cancel the y on the bottom with one y on the top and say you're done.
My edits: deleted overkill examples
mmm4444bot
Super Moderator
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- Oct 6, 2005
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Re: xy+y/y=????
Yes, this is the best way! It's the only way with more complex expressions.
Denis said:
Yes, this is the best way! It's the only way with more complex expressions.