(z - 1)/(z + 1) on an Argand diagram

burgerandcheese

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If z has modulus 1 and argument θ, where 0 < θ < π, find the modulus and argument of (z - 1)/(z + 1)

12549

I wanna know why the argument of (z + 1)/(z - 1) is "the angle you have to turn through to get from vector AP to vector BP, that is π/2 anticlockwise, or +π/2" What does that mean? Does it mean moving AP until it reaches BP? But isn't it always touching BP?

This came after learning the rules for multiplication and division in modulus-argument form

|st| = |s||t|, arg(st) = arg s + arg t + k(2π),
|s/t| = |s|/|t|, arg(s/t) = arg s - arg t + k(2π)
 
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Subhotosh Khan

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If z has modulus 1 and argument θ, where 0 < θ < π, find the modulus and argument of (z - 1)/(z + 1)

View attachment 12549

I wanna know why the argument of (z + 1)/(z - 1) is "the angle you have to turn through to get from vector AP to vector BP, that is π/2 anticlockwise, or +π/2" What does that mean? Does it mean moving AP until it reaches BP? But isn't it always touching BP?

This came after learning the rules for multiplication and division in modulus-argument form

|st| = |s||t|, arg(st) = arg s + arg t + k(2π),
|s/t| = |s|/|t|, arg(s/t) = arg s - arg t + k(2π)
That means "rotating" AP - centered at P - till it becomes co-linear (same-line) with BP.
 

burgerandcheese

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