I have the following question:

Z = (3-i)/(2+pi). The value of P must be real. If real value of Z = 1/2. find the value(s) of P.

First I have used the conjugate of (2+pi) in order to rationalize the denominator:

Z = (3-i)(2-pi)/(2+pi)(2-pi)

so: Z = pi^2 -2i - 3pi + 6/ 4-p^2i^2

But, if i^2 = -1, then:

Z = -p -2i -3pi + 6/ 4 + p^2

Where do I go from here?

Thanks