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I find this approach appealing because it avoids almost all algebra and works directly with the symmetry of the given products. Given... -
KI find this approach appealing because it avoids almost all algebra and works directly with the symmetry of the given products. Given...
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AAion replied to the thread Interesting little problem?.I find this approach appealing because it avoids almost all algebra and works directly with the symmetry of the given products. Given...
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Dr.Peterson replied to the thread Implicit Differentiation.That was said here: -
Nnasi112 replied to the thread Implicit Differentiation.I don't understand your steps here. You said u = xy \ln(x) Then you said \frac{dr}{dx} = \frac {dr}{du} \frac{du}{dx} But you did...
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NFirst, you need to give the full instructions for the problem. Presumably you are trying to do implicit differentiation, assuming y is a...
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PPenn replied to the thread arc in circle.T This is genuinely is just hieroglyphics if you translate it I can help you
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The Highlander replied to the thread Interesting little problem?.I've since discovered there are dozens of solutions already posted online, lol. Wasn't as original as I first thought. 🤷♂️ (eg...
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... or ... multiply all the equations together to get a^2b^2c^2=6000000 Square root and then divide by each equation.
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From the third equation c = \dfrac{300}{a} Plug into the second equation and simplify to get \dfrac{b}{a}=\dfrac{2}{3} so...
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Mmrtwhs replied to the thread Interesting little problem?.... or ... multiply all the equations together to get a^2b^2c^2=6000000 Square root and then divide by each equation.
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Mmrtwhs replied to the thread Interesting little problem?.From the third equation c = \dfrac{300}{a} Plug into the second equation and simplify to get \dfrac{b}{a}=\dfrac{2}{3} so...
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The Highlander replied to the thread Interesting little problem?.You need to show the solution (ie: the working) not just the answer (which is readily available through any Maths calculator App).
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Mmrtwhs replied to the thread Interesting little problem?.\dfrac{55 \sqrt{6}}{3} or \dfrac{-55 \sqrt{6}}{3}
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I thought this might be an interesting exercise for some to practise their algebra... ab = 100 bc = 200 ca = 300 Find the (exact)...
