## Minimum Number of Operations to Make Array Continuous solution leetcode

You are given an integer array `nums`

. In one operation, you can replace **any** element in `nums`

with **any** integer.

`nums`

is considered **continuous** if both of the following conditions are fulfilled:

- All elements in
`nums`

are**unique**. - The difference between the
**maximum**element and the**minimum**element in`nums`

equals`nums.length - 1`

.

For example, `nums = [4, 2, 5, 3]`

is **continuous**, but `nums = [1, 2, 3, 5, 6]`

is **not continuous**.

Return *the minimum number of operations to make *

`nums`

**.**

*continuous*

Minimum Number of Operations to Make Array Continuous solution leetcode

Input:nums = [4,2,5,3]Output:0Explanation:nums is already continuous.

**Example 2:**

Input:nums = [1,2,3,5,6]Output:1Explanation:One possible solution is to change the last element to 4. The resulting array is [1,2,3,5,4], which is continuous.

Minimum Number of Operations to Make Array Continuous solution leetcode

Input:nums = [1,10,100,1000]Output:3Explanation:One possible solution is to: - Change the second element to 2. - Change the third element to 3. - Change the fourth element to 4. The resulting array is [1,2,3,4], which is continuous.

**Constraints:**

`1 <= nums.length <= 10`

^{5}`1 <= nums[i] <= 10`

^{9}

Minimum Number of Operations to Make Array Continuous solution leetcode – ravilrajasthan