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Intermediate/Advanced Algebra
For more advanced algebra topics, including Algebra II and Pre-Calculus.
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A Linear Algerbra Question Regarding Span, Linear Independence and Base
The Student
Jan 6, 2014
Replies
2
Views
1K
Jan 6, 2014
The Student
T
J
Summation of a complex number from 0 to infinity
junam
Dec 31, 2013
Replies
5
Views
2K
Jan 6, 2014
junam
J
P
Trying to understand logistic model of sequences
Probability
Jan 6, 2014
Replies
0
Views
1K
Jan 6, 2014
Probability
P
G
standard form: (1.6 * 10^a) * (8 * 10^b) = c * 10^4
gortwell
Dec 30, 2013
Replies
13
Views
4K
Jan 6, 2014
gortwell
G
D
Sucker bet, my (almost) bad.
Dale10101
Jan 5, 2014
Replies
7
Views
3K
Jan 6, 2014
Dale10101
D
M
SI units?
MrsV13
Jan 6, 2014
Replies
1
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1K
Jan 6, 2014
JeffM
J
A
Slope for square root equation
andreo
Jan 4, 2014
Replies
5
Views
9K
Jan 6, 2014
JeffM
J
G
What is the multiplicative inverse of -9-17i?
GrannySmith
Jan 5, 2014
Replies
3
Views
2K
Jan 5, 2014
pka
G
How to simplify radicals
GrannySmith
Jan 4, 2014
Replies
9
Views
4K
Jan 5, 2014
JeffM
J
R
more on rational exponents
richardt
Jan 4, 2014
Replies
8
Views
3K
Jan 5, 2014
richardt
R
A
Complex numbers, cartesian to polar
Anthonyk2013
Jan 4, 2014
Replies
9
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3K
Jan 4, 2014
Quaid
Q
K
AFM killing me right now..
katymoses
Jan 4, 2014
Replies
1
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2K
Jan 4, 2014
pka
T
inequalities
triggg
Jan 3, 2014
Replies
3
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1K
Jan 4, 2014
Quaid
Q
H
R = 15t^2 – 120t + 250: find the value of t for which....
harith
Dec 30, 2013
Replies
16
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20K
Jan 4, 2014
Dale10101
D
T
transformations of functions
teddy7
Jan 3, 2014
Replies
1
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1K
Jan 4, 2014
lookagain
L
D
The quadratic equation.
Dale10101
Jan 3, 2014
Replies
4
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2K
Jan 3, 2014
Dale10101
D
H
Solve fg(x) = 0 for f: x -> x^2 - 4, g: x -> 3x - 2
harith
Jan 1, 2014
Replies
4
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3K
Jan 2, 2014
harith
H
D
Simplifying Radical Expressions
DanthePolishman
Dec 31, 2013
Replies
6
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3K
Jan 1, 2014
DanthePolishman
D
D
Product of log problem
Dale10101
Dec 30, 2013
Replies
1
Views
1K
Dec 31, 2013
Dale10101
D
A
If (x^4)+(ax^3)+(bx^2)+(cx)+81=0 has 4 real roots, then...
Akshar
Dec 27, 2013
Replies
4
Views
3K
Dec 30, 2013
Akshar
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