G goodstudent12 New member Joined Oct 24, 2018 Messages 1 Oct 24, 2018 #1 I can't solve this equation: Given the equation below, solve for x: . . . . .\(\displaystyle 2\, \sin^2(x)\, -\, \dfrac{5}{2}\, \sin(2x)\, -\, \cos^2(x)\, +\, 2\, =\, 0\) Thank you Attachments Untitled.png 3.2 KB · Views: 3 Last edited by a moderator: Oct 28, 2018
I can't solve this equation: Given the equation below, solve for x: . . . . .\(\displaystyle 2\, \sin^2(x)\, -\, \dfrac{5}{2}\, \sin(2x)\, -\, \cos^2(x)\, +\, 2\, =\, 0\) Thank you
D Deleted member 4993 Guest Oct 24, 2018 #2 goodstudent12 said: I can't solve this equation: Given the equation below, solve for x: . . . . .\(\displaystyle 2\, \sin^2(x)\, -\, \dfrac{5}{2}\, \sin(2x)\, -\, \cos^2(x)\, +\, 2\, =\, 0\) Thank you Click to expand... 2*sin^2(x) - 5/2 * sin(2*x) - cos^2(x) + 2 = 0 3*sin^2(x) - 5 * sin(x) * (1- sin^2(x))^(1/2) + 1 = 0 continue.... Last edited by a moderator: Oct 28, 2018
goodstudent12 said: I can't solve this equation: Given the equation below, solve for x: . . . . .\(\displaystyle 2\, \sin^2(x)\, -\, \dfrac{5}{2}\, \sin(2x)\, -\, \cos^2(x)\, +\, 2\, =\, 0\) Thank you Click to expand... 2*sin^2(x) - 5/2 * sin(2*x) - cos^2(x) + 2 = 0 3*sin^2(x) - 5 * sin(x) * (1- sin^2(x))^(1/2) + 1 = 0 continue....
