exam tomorrow: Solve 2sin^2(x) - (5/2) sin(2x) - cos^2(x) + 2 = 0

[goodstudent12]

I can't solve this equation:

Given the equation below, solve for x:

. . . . .\(\displaystyle 2\, \sin^2(x)\, -\, \dfrac{5}{2}\, \sin(2x)\, -\, \cos^2(x)\, +\, 2\, =\, 0\)

Thank you

 

[Deleted member 4993]

I can't solve this equation:

Given the equation below, solve for x:

. . . . .\(\displaystyle 2\, \sin^2(x)\, -\, \dfrac{5}{2}\, \sin(2x)\, -\, \cos^2(x)\, +\, 2\, =\, 0\)

Thank you

2*sin^2(x) - 5/2 * sin(2*x) - cos^2(x) + 2 = 0

3*sin^2(x) - 5 * sin(x) * (1- sin^2(x))^(1/2) + 1 = 0

continue....