I am not seeing this one. What's next?Knowing that a radius of a circle which meets a tangent to the circle is perpendicular to that tangent, can you begin by giving the measures of the 4 interior angles of the quadrilateral ABYX?
I actually did that before reading your post. This is where I am getting stuck.Next, I would draw the line segment BX and a segment from X perpendicular to BY which gives us two triangles with which to work...
I actually did that before reading your post. This is where I am getting stuck.
Maybe it is too late for me to be doing math. I guess I will see this in the morning.
I would draw XC parallel to AB, and consider triangle XYC. One approach is to name the radii x and y; then XY = x+y and DY = y-x. You can solve for y/x, and use that to find angle BXC. I haven't carried it out, but it should work.Hello! This is a problem I've been struggling with in my Geometry class and I was hoping someone could help walk me through the steps for my upcoming test.
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Thank you so much in advance! :]
-Rinn
What is next is same...I was only wondering why circles are used...If I agree with that, then what is next?
So the problem could be stated this shorter way:
Quadrilateral ABYX with angles A=90, B=90, Y=75, X=105.
Calculate angle ABX.
Y'all agree?
We also know that XY = AX + BY, in addition to the angles. With only the angles, there would not be enough information.What is next is same...I was only wondering why circles are used...
Ah So! Dumb me missed that...with trig, I now get angle BXY = 35We also know that XY = AX + BY, in addition to the angles. With only the angles, there would not be enough information.
I'm not including the 15 degrees: 35.989984... if I did; so we agree...I got a little less than 36 degrees by trig, which agrees with a drawing.