I actually did that before reading your post. This is where I am getting stuck.Next, I would draw the line segment BX and a segment from X perpendicular to BY which gives us two triangles with which to work...
I haven't actually solved the problem, I was just posting suggestions I felt would lead to the solution.I actually did that before reading your post. This is where I am getting stuck.
Maybe it is too late for me to be doing math. I guess I will see this in the morning.
I would draw XC parallel to AB, and consider triangle XYC. One approach is to name the radii x and y; then XY = x+y and DY = y-x. You can solve for y/x, and use that to find angle BXC. I haven't carried it out, but it should work.
So the problem could be stated this shorter way:
Quadrilateral ABYX with angles A=90, B=90, Y=75, X=105.
Calculate angle ABX.
We also know that XY = AX + BY, in addition to the angles. With only the angles, there would not be enough information.What is next is same...I was only wondering why circles are used...