i need help .really need to understand how to do this step by step. plz help someone. Question 7

[dev644]

 

[ksdhart2]

You're told that this particular polynomial has two equal roots. In order for this to be the case, what must be true about the discriminant of the polynomial? Which value(s) of \(a\) ensure this condition holds?

 

[dev644]

OK thanks, I have solved it. Great community, keep the good work☺

 

[Denis]

Could you post your solution: it may help another student.
Thank you.

 

[pka]

Find the value of \(\displaystyle a\) that causes \(\displaystyle (3a-2)x^2-6ax+4a+1=0\) has a double root.

To have a double root the discriminate must be zero:
\(\displaystyle \Delta=(-6a)^2-4(3a-2)(4a+1)=0\) SEE HERE

If \(\displaystyle a=2\) the root is \(\displaystyle 1.5\) SEE HERE

If \(\displaystyle a=\frac{-1}{3}\)then the root is \(\displaystyle \frac{1}{3}\) SEE HERE

 

[Denis]

well...in other words...b^2 = 4ac

 

[dev644]

Why are u angry jomo?