- Thread starter dev644
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To have a double root the discriminate must be zero:Find the value of \(\displaystyle a\) that causes \(\displaystyle (3a-2)x^2-6ax+4a+1=0\) has a double root.

\(\displaystyle \Delta=(-6a)^2-4(3a-2)(4a+1)=0\) SEE HERE

If \(\displaystyle a=2\) the root is \(\displaystyle 1.5\) SEE HERE

If \(\displaystyle a=\frac{-1}{3}\)then the root is \(\displaystyle \frac{1}{3}\) SEE HERE