Not in this exercise. 3r = r when y=x^2, but we can't express a in terms of b and c, for that polynomial.Can r and 3r be equal????
The quadratic formula gives the two roots, in terms of parameters a,b,c. You could multiply one of them by 3 and set the result equal to the other. Solve that equation for a, for b and for c.I have no clue how to start
Why not y = ax^2 + bx?? Recall if 3r = r then r= 0 and x= r =0 is a root of y=ax^2 + bx.Not in this exercise. 3r = r when y=x^2, but we can't express a in terms of b and c, for that polynomial.
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It seems that you answered your own question, Jomo. The roots of ax^2+bx are 0 and -b/a.Why not y = ax^2 + bx? …