Probability
Full Member
- Joined
- Jan 26, 2012
- Messages
- 425
So I'm really struggling with the understanding of how to interpret the English questions being asked when trying to create a formula. This is a serious lack of experience on my part, but is there a way of interpreting the questions to create the math formulas in a straight forward type of way.
In this question I was asked;
A machine company charges £250 to print 400 labels of an agreed size. If further labels are then required another agreement is to charge an extra £0.25 per label.
I'm asked to find a formula for the cost C of printing the labels, assuming that (n) is at least 400. I've been working on this on and off most of the day, and I don't find this type of math easy to work out. I decided that C would be the total cost and (n) would be the cost of additional labels. I eventually came up with this formula;
[MATH]{C}={250}+{0.25}({n}-{400})[/MATH] I then was asked to simplify the formula;
[MATH]{C}={250}+{0.25n}-{100}=[/MATH]
[MATH]{C}={150}+{0.25n}[/MATH]
I was then asked to use the formula to find the cost of another 450 labels.
[MATH]{C}={150}+{0.25}\times{450}=[/MATH]
[MATH]{C}={150}+{112.50}=£287.50[/MATH]
In this question I was asked;
A machine company charges £250 to print 400 labels of an agreed size. If further labels are then required another agreement is to charge an extra £0.25 per label.
I'm asked to find a formula for the cost C of printing the labels, assuming that (n) is at least 400. I've been working on this on and off most of the day, and I don't find this type of math easy to work out. I decided that C would be the total cost and (n) would be the cost of additional labels. I eventually came up with this formula;
[MATH]{C}={250}+{0.25}({n}-{400})[/MATH] I then was asked to simplify the formula;
[MATH]{C}={250}+{0.25n}-{100}=[/MATH]
[MATH]{C}={150}+{0.25n}[/MATH]
I was then asked to use the formula to find the cost of another 450 labels.
[MATH]{C}={150}+{0.25}\times{450}=[/MATH]
[MATH]{C}={150}+{112.50}=£287.50[/MATH]