What you wrote here doesn't make sense.Could someone assist me with solving this problem please? I am trying to find f from the second derivative.
f ″(x) = 5ex − 7 sin(x), f(0) = 3, f (pi/2)=0
It could be a boundary value problem (like a vibrating string) - however I have not worked through.You'd also need a condition for the first derivative to solve for the constant. Do you mean f'(0)=3 or f'(pi/2)=0. One of those is missing the prime sign.
Perhaps, post an image of the problem instead. Also, please share what you have tried so far.
Sorry, I meant f ″(x) = 5e^x − 7 sin(x). And yes the conditions were f'(0)=3 or f'(pi/2)=0.What you wrote here doesn't make sense.
What's 5ex? Do you mean 5e^x?
You'd also need a condition for the first derivative to solve for the constant. Do you mean f'(0)=3 or f'(pi/2)=0. One of those is missing the prime sign.
Perhaps, post an image of the problem instead. Also, please share what you have tried so far.
Are you sure you have an "or" ?Sorry, I meant f ″(x) = 5e^x − 7 sin(x). And yes the conditions were f'(0)=3 or f'(pi/2)=0.
Why do math students have so much problems with AND and OR? These are words that they use everyday but when it comes to math they forget the meanings.Are you sure you have an "or" ?
Moreover, now you have prime over both the given conditions! Is that correct?
Wow, I mistyped the question again I'm sorry. I have been struggling with this topic for the past few days. I am trying to find f forAre you sure you have an "or" ?
Moreover, now you have prime over both the given conditions! Is that correct?
Not necessarily.Shouldn't one of those last two functions have a prime?
Have you tried integrating f"(x)Could someone assist me with solving this problem please? I am trying to find f from the second derivative.
f ″(x) = 5e^x − 7 sin(x), f(0) = 3, f (pi/2)=0 ..........edited