How I solve it

[shahar]

The question is:

a and b are whole numbers.
Given: a + b = 4(a - b)
hence:
b divided by the factor:
(1) 8
(2) 7
(3) 3
(4) 5

Can somebody help me with it?
I don't have the answer.
Happy New Year (Hebrew Year).

 

[pka]

The question is: a and b are whole numbers. Given: a + b = 4(a - b) hence:
b divided by the factor:
(1) 8 (2) 7 (3) 3 (4) 5
Can somebody help me with it?
I don't have the answer.
Happy New Year (Hebrew Year).

[imath]a+b=4(a-b) \Rightarrow 3a-5b=0[/imath]
Beyond that, I have not a clue what your question means.

 

[shahar]

I try to edit it:
The variables a and b are whole numbers.

Given: a + b = 4(a - b)

necessarily,
b divided by the multiplier:
(1) 8
(2) 7
(3) 3
(4) 5

Can somebody help me with it?

 

[shahar]

[imath]a+b=4(a-b) \Rightarrow 3a-5b=0[/imath]
Beyond that, I have not a clue what your question means.

Now am I clear to you?

 

[blamocur]

b divided by the multiplier:

b is guaranteed to be divisible by which multiplier? @pka's hint in post #2 can be quite helpful in figuring out the answer.

 

[shahar]

b is guaranteed to be divisible by which multiplier? @pka's hint in post #2 can be quite helpful in figuring out the answer.

Is in the answer 3 or 5?
I thinks the answer number 3 because the variable a is a whole number so it guaranteed to be dividable by 3.
I want to formulate an answer. How I do it?

 

[shahar]

I meant:
to formulate = to write.
I want to write an answer with descriptions. How do I do It?

 

[Deleted member 4993]

The question is:

a and b are whole numbers.
Given: a + b = 4(a - b)
hence:
b divided by the factor:
(1) 8
(2) 7
(3) 3
(4) 5

Can somebody help me with it?
I don't have the answer.
Happy New Year (Hebrew Year).

a + b = 4a - 4b

a = (5/3) * b ********************************corrected

3 and 5 are relatively prime and

a & b are integers, - hence

3|b ********************************corrected

Continue.....

 

[lookagain]

a + b = 4a - 4b
. . .
3 and 5 are relatively prime and
a & b are integers, - hence
5|b \(\displaystyle \ \ \ \) ?

Subhotosh Khan,

a + b = 4a - 4b

5b = 3a

3 does not divide 5, because they are relatively prime,
and a & b are integers.

Hence, it remains that \(\displaystyle \ \) 3|b.

 

[Deleted member 4993]

Subhotosh Khan,

a + b = 4a - 4b

5b = 3a

3 does not divide 5, because they are relatively prime,
and a & b are integers.

Hence, it remains that \(\displaystyle \ \) 3|b.

You are correct - I made a mistake. That should have been

3*a = 5*b → b|3

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