[imath]a+b=4(a-b) \Rightarrow 3a-5b=0[/imath]The question is: a and b are whole numbers. Given: a + b = 4(a - b) hence:
b divided by the factor:
(1) 8 (2) 7 (3) 3 (4) 5
Can somebody help me with it?
I don't have the answer.
Happy New Year (Hebrew Year).
Now am I clear to you?[imath]a+b=4(a-b) \Rightarrow 3a-5b=0[/imath]
Beyond that, I have not a clue what your question means.
Is in the answer 3 or 5?b is guaranteed to be divisible by which multiplier? @pka's hint in post #2 can be quite helpful in figuring out the answer.
a + b = 4a - 4bThe question is:
a and b are whole numbers.
Given: a + b = 4(a - b)
hence:
b divided by the factor:
(1) 8
(2) 7
(3) 3
(4) 5
Can somebody help me with it?
I don't have the answer.
Happy New Year (Hebrew Year).
a + b = 4a - 4b
. . .
3 and 5 are relatively prime and
a & b are integers, - hence
5|b \(\displaystyle \ \ \ \) ?
You are correct - I made a mistake. That should have beenSubhotosh Khan,
a + b = 4a - 4b
5b = 3a
3 does not divide 5, because they are relatively prime,
and a & b are integers.
Hence, it remains that \(\displaystyle \ \) 3|b.