**Re: Algebra help**
lalcasio said:

Solve (1)\(\displaystyle \L \;3-2(x+3)+2=1\;\) and (2)\(\displaystyle \L \;1/3(t-5)\,=\,6\;\)

(3)If a blue heroin that measures 3.5 incehes in the photo is actually 3.75 feet tall approximately how long is its beak of it measures 0.4 inchesin the photo.

1) \(\displaystyle \L 3\,-\,2\,(x\,+\,3)\,+\,2\,=\,1\;\)

\(\displaystyle \L 3\,-\,2x\,-\,6\,+\,2\,=\,1\)

\(\displaystyle \L -\,2x\,-\,1\,=\,1\)

\(\displaystyle \L -\,2x\,=\,2\)

\(\displaystyle \L x\,=\,-\,1\)

So:\(\displaystyle \L \;3\,-\,2\,(\,-\,1\,+\,3)\,+\,2\,=\,1\;\)

On the second I'm gonna go out on my and say you mean: \(\displaystyle \L \;\frac{1}{3(t\,-\,5)}\,=\,6\)

2) \(\displaystyle \L \;\frac{1}{3t\,-\,15}\,=\,\frac{6}{1}\)

Criss - Cross Multiplication:\(\displaystyle \L \;1\,=\,18t\,-\,90\)

\(\displaystyle \L \;90\,=\,18t\)

\(\displaystyle \L \;t\,=\,5\)

3) Ok lets make a proportional proportion!

\(\displaystyle \L \frac{3.5}{3.75}\,=\,\frac{.4}{x}\)

\(\displaystyle \L 1.5\,=\,3.5x\)

\(\displaystyle \L x\,=\,.428571429\,\to\,\approx.43\,in.\)