cannot solve please help x2/x-3=x2/1x3=(x2)(x3)=x3
R rrolo31 New member Joined Dec 26, 2009 Messages 1 Dec 26, 2009 #1 cannot solve please help x2/x-3=x2/1x3=(x2)(x3)=x3
A Aladdin Full Member Joined Mar 27, 2009 Messages 553 Dec 26, 2009 #2 rrolo31 said: cannot solve please help x2/x-3=x2/1x3=(x2)(x3)=x3 Click to expand... What's this ! Please type clearer .
rrolo31 said: cannot solve please help x2/x-3=x2/1x3=(x2)(x3)=x3 Click to expand... What's this ! Please type clearer .
S soroban Elite Member Joined Jan 28, 2005 Messages 5,586 Dec 26, 2009 #3 Helolo, rrolo31! cannot solve please help x2/x-3=x2/1x3=(x2)(x3)=x3 Click to expand... Even with my wildest guessing, it doesn't make any sense . . . \(\displaystyle \frac{x^2}{x}-3 \;=\;\frac{x^2}{1x^3} \;=\;(x^2)(x^3) \;=\;x^3\) \(\displaystyle \frac{x^2}{x-3} \;=\;\frac{x^2}{1\times3} \;=\;(x^2)(x^3) \;=\;x^3\) What is the equation ?
Helolo, rrolo31! cannot solve please help x2/x-3=x2/1x3=(x2)(x3)=x3 Click to expand... Even with my wildest guessing, it doesn't make any sense . . . \(\displaystyle \frac{x^2}{x}-3 \;=\;\frac{x^2}{1x^3} \;=\;(x^2)(x^3) \;=\;x^3\) \(\displaystyle \frac{x^2}{x-3} \;=\;\frac{x^2}{1\times3} \;=\;(x^2)(x^3) \;=\;x^3\) What is the equation ?
C chrisr Full Member Joined Nov 29, 2009 Messages 355 Dec 26, 2009 #4 Looks like the student tried to label subscripts \(\displaystyle \frac{x_2}{x-3}=\frac{x_2}{x_3}=(x_2)(x_3)=x_3\) giving \(\displaystyle x_2=1\) \(\displaystyle (x_3)^2=1,\quad x_3=1\quad or\quad -1\) \(\displaystyle x=2\quad or\quad 4\)
Looks like the student tried to label subscripts \(\displaystyle \frac{x_2}{x-3}=\frac{x_2}{x_3}=(x_2)(x_3)=x_3\) giving \(\displaystyle x_2=1\) \(\displaystyle (x_3)^2=1,\quad x_3=1\quad or\quad -1\) \(\displaystyle x=2\quad or\quad 4\)