- Thread starter CAS52
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Hint: assume that the lowest score was 0.The average of 7 tests is 69%. If lowest score is removed what is the highest possible remaining percentage for the remaining 6 tests?

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Correct!I multiplied 69% by 7 getting 483

Then divided 483 by 6 to get 80.5 but felt that was too easy?

All problems are easy!!

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Sorry but 69% times 7 is NOT 483. After all 69% is less than 1. How can a number less than 1 multiplied by a small number like 7 give you 483! Be more careful. Might you have meant that 69*7 is 483I multiplied 69% by 7 getting 483

Then divided 483 by 6 to get 80.5 but felt that was too easy?

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Hint: assume that the lowest score was 0.

Please show us what you have tried and exactly where you are stuck.

Please follow the rules of posting in this forum, as enunciated at:

READ BEFORE POSTING

Please share your work/thoughts about this problem.

Thank you for replying.of7= 0.69(7)= 4.83. 4.83/6= 0.805 or 80.5% so if you are careful to state that the result is a percent, you got the right answer!

I did mean 69 x 7.Sorry but 69% times 7 is NOT 483. After all 69% is less than 1. How can a number less than 1 multiplied by a small number like 7 give you 483! Be more careful. Might you have meant that 69*7 is 483

Thank you so much for replyingof7= 0.69(7)= 4.83. 4.83/6= 0.805 or 80.5% so if you are careful to state that the result is a percent, you got the right answer!

Thank you for replyingCorrect!

All problems are easy!!