i folks,

This is my first post so please accept my aplologies if it's not quite right.

I'm doing a basic maths course, but this one equation is driving me mad. I know the answer is 2.8 by typing it in to a equation solver, and it resolves correctly, however I just can see how it's worked out.

y=0.25t^2-2t+4 were y=0.36

If some kind person could offer some help, I'd be very grateful.

Many thanks in advance.

Alan

Since we have no idea as to your level of knowledge, it is hard to know at what level to provde the solutoion.

1--You were given the equation y = .25t^2 - 2t + 4 where y = .36.

2--For y = .36 we subtract .36 from both sides end up with .25t^2 - 2t + 3.64 = 0 or t^2 - 8t + 14.56 = 0, after dividing through by .25.

3--From the standard format of a quadratic equation, ax^2 + bx + c = 0, the quadratic formuls x = [-b+/-sqrt(b^2 - 4ac]/2a was derived for solving the equation.

4--Using the quadratic equation, t = [+8+/-sqrt(8^2 - 4(1)3.64)]/2

5--t = [+8+/-sqrt(8^2 - 4(1)3.64)]/2 = [8+/-sqrt(5.76)]/2

6--t = [8 +/-2.4]/2 = 10.46/2 = 5.2 or 5.6/2 = 2.8

I do hope this clears up any problems you were having understanding the solution path.