Can you help me?? Frustrating Prob yo.

[thisyearsdude]

How many quarts of a pure solution must be added to 5% solution to get 4 quarts of a 14.5% solution ??




thnx for any solutions.

 

[stapel]

Why is this posted to calculus...?

Using algebraic methods:

. . . . .quarts solution:
. . . . .5%: x
. . . . .pure: 4 - x
. . . . .mix: 4

. . . . .percent solute:
. . . . .5%: 0.05
. . . . .pure: 1
. . . . .mix: 0.04

. . . . .quarts solute:
. . . . .5%: 0.05(x)
. . . . .pure: ...?
. . . . .mix: ...?

Add the inputs, set equal to the output, and solve.

Eliz.

 

[Guest]

Let x be the amount of pure solution

then you will have (4-x) of the 5% solution

(100%) x + (5%) (4-x) = (14.5%) (4)

x +0.05 (4-x) =0.145 (4)

solve for x.....