Complicated Limit Problems

jonah2.0

Full Member
Beer soaked ramblings follow.
Just from the image of the exercise you put in the first post in this thread.
That must have been an exhausting search.
I was almost sure you've seen his posts where he kept mentioning the author's name.

lex

Full Member
Beer soaked ramblings follow.

That must have been an exhausting search.
I was almost sure you've seen his posts where he kept mentioning the author's name.
That would have been too easy!

Junior Member
Just from the image of the exercise you put in the first post in this thread.
Brother, if you are going to help me with my threads by providing hints and insight, terrific. If you are simply looking to leave a comment here and there without leading to math help, then please move on. Nothing personal, of course.

lookagain

Elite Member
Brother, ...

nycmathdad, in post # 15 and highlighted above in post # 23, you addressed
a member incorrectly. They are not "brother" to you. You are to use their

lex

Junior Member
nycmathdad, in post # 15 and highlighted above in post # 23, you addressed
a member incorrectly. They are not "brother" to you. You are to use their
And???

lookagain

Elite Member

nycmathdad, no, that response from you does not make sense.
If anything, something along the lines of this one would:

I understand.

Else, you are adding to a history of uncivil/argumentative/demanding
messages in posts that counter to the forum rules.

lex

Full Member
Just from the image of the exercise you put in the first post in this thread.
Brother, if you are going to help me with my threads by providing hints and insight, terrific. If you are simply looking to leave a comment here and there without leading to math help, then please move on. Nothing personal, of course.
This comment was a reply to a question you asked me twice - in post #16 and post #20. I hoped that post #5 would have been helpful to you in completing your questions.
Goodbye and good luck with your mathematical studies.

Subhotosh Khan

Super Moderator
Staff member
Expanding on suggestions by DrP (response #4), use:

(p + q) * (p - q) = p2 - q2

Junior Member
This comment was a reply to a question you asked me twice - in post #16 and post #20. I hoped that post #5 would have been helpful to you in completing your questions.
Goodbye and good luck with your mathematical studies.
Thanks, brother.