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Compound continously
- Thread starter pewpewm
- Start date
I'm not sure what I'm doing wrong on B! I understand it is 500*e^0.1+500e^0.2....
But I can't seem to find the formula to SUM it all together without just basically adding each part to the next.
\(\displaystyle S_n \ = \ \dfrac{a(r^n - 1)}{r - 1}, \ \) where a is the first term, n is the number of terms,
r is the common ratio (not equal to 1), and \(\displaystyle \ S_n \ \) is the sum.
If your sum is supposed to be 500*e^0.1 + 500*e^0.2 + ... + 500*e^1, then you
could start by writing it as this before applying the formula to what is inside the parentheses:
500e^0.1(1 + e^0.1 + ... + e^0.9)
Thanks for the reply. I still don't get it nor do I get the accurate answer.\(\displaystyle S_n \ = \ \dfrac{a(r^n - 1)}{r - 1}, \ \) where a is the first term, n is the number of terms,
r is the common ratio (not equal to 1), and \(\displaystyle \ S_n \ \) is the sum.
If your sum is supposed to be 500*e^0.1 + 500*e^0.2 + ... + 500*e^1, then you
could start by writing it as this before applying the formula to what is inside the parentheses:
500e^0.1(1 + e^0.1 + ... + e^0.9)
I'm a bit too slow today for this to make any sense!