Compound continously

[pewpewm]

Hey guys!

I have this questions here;



I'm not sure what I'm doing wrong on B! I understand it is 500*e^0.1+500e^0.2....

But I can't seem to find the formula to SUM it all together without just basically adding each part to the next.

 

[lookagain]

I'm not sure what I'm doing wrong on B! I understand it is 500*e^0.1+500e^0.2....

But I can't seem to find the formula to SUM it all together without just basically adding each part to the next.

$\displaystyle S_n \ = \ \dfrac{a(r^n - 1)}{r - 1}, \$ where a is the first term, n is the number of terms,
r is the common ratio (not equal to 1), and $\displaystyle \ S_n \$ is the sum.


If your sum is supposed to be 500*e^0.1 + 500*e^0.2 + ... + 500*e^1, then you
could start by writing it as this before applying the formula to what is inside the parentheses:

500e^0.1(1 + e^0.1 + ... + e^0.9)

 

[pewpewm]

$\displaystyle S_n \ = \ \dfrac{a(r^n - 1)}{r - 1}, \$ where a is the first term, n is the number of terms,
r is the common ratio (not equal to 1), and $\displaystyle \ S_n \$ is the sum.


If your sum is supposed to be 500*e^0.1 + 500*e^0.2 + ... + 500*e^1, then you
could start by writing it as this before applying the formula to what is inside the parentheses:

500e^0.1(1 + e^0.1 + ... + e^0.9)

Thanks for the reply. I still don't get it nor do I get the accurate answer.

I'm a bit too slow today for this to make any sense!