- Thread starter burt
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Do a little research using google search!As far as I can tell, a transcendental number goes on forever without being able to be expressed in terms of any sort of rational expression. How is this different than the term irrational number?

Please let us know what you find - or need further clarification.

My google etc research is how I came up with this definition to begin with... Am I misunderstanding it?Do a little research using google search!

Please let us know what you find - or need further clarification.

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Both transcendental and irrational numbers "go on forever", meaning they have non-terminating non-repeating decimal expansions. That is the equivalent of the definition of an irrational number, but not a transcendental one. Google "transcendental number". You will find lots of information.My google etc research is how I came up with this definition to begin with... Am I misunderstanding it?

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Here's a list of a few. It's very hard to prove that a number is transcendental. You have to show that the number is not the zero of any polynomial with integer coefficients.Are there any other known transcendental numbers besides for \(\displaystyle e\) and \(\displaystyle \pi\)?

It's not just square roots. For example, \(\displaystyle \sqrt{ 1 + \sqrt{3} } + 3\) is irrational but not transcendental.

Here's a list of a few.

-Dan

you want to look at the definition of "algebraic" numbers. Irrational numbers are simply that, not rational. Both the sets ofI think I found the difference - irrational numbers may be able to be expressed as a root of a rational number ie: \(\displaystyle \sqrt{2}\) but transcendental numbers cannot.

algebraic numbers and transcendental numbers are subsets of the irrationals.

By "known" I think you mean labeled. The golden ratio is another transcendental number given a name. The vast bulk of numbers are transcendental.

Both the set of algebraic numbers and the set of rationals have measure zero.

Does this mean more numbers are transcendental than not? How is that?you want to look at the definition of "algebraic" numbers. Irrational numbers are simply that, not rational. Both the sets of

algebraic numbers and transcendental numbers are subsets of the irrationals.

By "known" I think you mean labeled. The golden ratio is another transcendental number given a name. The vast bulk of numbers are transcendental.

Both the set of algebraic numbers and the set of rationals have measure zero.

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The golden ratio is NOT a transcendental number. It is root of xyou want to look at the definition of "algebraic" numbers. Irrational numbers are simply that, not rational. Both the sets of

algebraic numbers and transcendental numbers are subsets of the irrationals.

By "known" I think you mean labeled. The golden ratio is another transcendental number given a name. The vast bulk of numbers are transcendental.

Both the set of algebraic numbers and the set of rationals have measure zero.

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Yes. The rationals and the algebraic numbers are both countable infinity. The transcendentals are an uncountable infinity.Does this mean more numbers are transcendental than not? How is that?

orly... my badThe golden ratio is NOT a transcendental number. It is root of x^{2}- x - 1 = 0

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YesAre there any other known transcendental numbers besides for \(\displaystyle e\) and \(\displaystyle \pi\)?

One being

2

e

Log

Please read:

http://mathworld.wolfram.com/TranscendentalNumber.html

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Read:Does this mean more numbers are transcendental than not? How is that?

https://www.scientificamerican.com/article/strange-but-true-infinity-comes-in-different-sizes/

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Can we please a proof of this. I'm not say you are wrong, I just want to see this proof.Yes. The rationals and the algebraic numbers are both countable infinity. The transcendentals are an uncountable infinity.

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For that you have to read a paper by George Cantor. Internet is full of reference to that paper.Can we please a proof of this. I'm not say you are wrong, I just want to see this proof.