cos ( 2x ) = cos^2 ( (3x)/(2) ) Solve for x, without a specified interval. I'm not really sure where to start, what I first did was I expanded the cos^2 ( (3x)/(2) ) into cos^2 ( (3x + 0)/(2) ) cos^2 ( (3x - 0)/(2) ) using the cos(a) + cos(b) identity I then simplified it into (cos(3x) +...
Right! But this is a perfect example why there should be some way to correct a post that is carried through the entire thread.
In all fairness, you must admit that posts after #2 still assumed 'prove' and not 'solve'.
Yea sorry I miss typed the original post and corrected it in a second post but i guess most of you didn't see it, that's my bad. It didn't let me edit what I wrote so I just posted again saying that. Either way like @MarkFL said, I did post this question previously and I was helped with it. I forgot how to do it I guess and forgot i posted about it. (I've been doing tons of different types of math questions these past few weeks and I guess I got lost). My mistake sorry for that.