(y^3 - 11y^2 + 6) / (y^2 - 3)
when I divide the first term by the first term y^3/y^2 I get y
then multiple y above by the divisor (y^2-3) I get y^3-3y how can i subtract 11y^2 - 3y they are two different degree
help have I done something wronge in my math
Please help
Thank you
when I divide the first term by the first term y^3/y^2 I get y
then multiple y above by the divisor (y^2-3) I get y^3-3y how can i subtract 11y^2 - 3y they are two different degree
help have I done something wronge in my math
Please help
Thank you