Ellipse help

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Hejzara

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Find the lines that are tangent to the elipse x2+2y2=12 and paralel to x+y-2=0 ??? Can soneone solve this please..
 
Hejzara said:
Find the lines that are tangent to the ellipse \(x^2+2y^2=12\) and parallel to \(x+y-2=0\) ? Can someone solve this please.
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As part of the rules of this forum , you are required to post some of your own work.
The slope of the line \(x+y-2=0\) is \(-1\). Where on the ellipse \(x^2+2y^2=12\) are the tangents \(-1~?\)
 
What work? I just need to answer this last question for my exam... question looks like this in Serbian language
 

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"What work?" The work you have done to try to answer this problem! Are you used to looking at a problem and being able to immediately write down the answer without doing any work?

And now that you tell us it is for an exam, I have erased the suggestions I had previously made.
 
Hejzara said:
What work? I just need to answer this last question for my exam... question looks like this in Serbian language
Click to expand...
The work is what YOU produce to answer the question in YOUR exam!!

What have YOU produced?
 
Oh man, ok, ok, my bad don't be like that. So...
x2+2y2=12
d/dx(x2)+d/dx(2y2)=d/dx(12)
2x+d/dx(2y2)=d/dx(12)
2x+d/dy(2y2)×dy/dx=d/dx(12)
2x+d/dy(2y2)×dy/dx=0
2x+2×d/dy(y2)×dy/dx=0
2x+2×2y×dy/dx=0
2x+4y×dy/dx=0
4y×dy/dx=-2x
dy/dx=-x/2y
 
Hejzara said:
Oh man, ok, ok, my bad don't be like that. So...
x2+2y2=12
d/dx(x2)+d/dx(2y2)=d/dx(12)
2x+d/dx(2y2)=d/dx(12)
2x+d/dy(2y2)×dy/dx=d/dx(12)
2x+d/dy(2y2)×dy/dx=0
2x+2×d/dy(y2)×dy/dx=0
2x+2×2y×dy/dx=0
2x+4y×dy/dx=0
4y×dy/dx=-2x
dy/dx=-x/2y
Click to expand...
How would you this information for your problem?

Look at response 2.
 
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