As part of the rules of this forum , you are required to post some of your own work.Find the lines that are tangent to the ellipse \(x^2+2y^2=12\) and parallel to \(x+y-2=0\) ? Can someone solve this please.
The work is what YOU produce to answer the question in YOUR exam!!What work? I just need to answer this last question for my exam... question looks like this in Serbian language
How would you this information for your problem?Oh man, ok, ok, my bad don't be like that. So...
x2+2y2=12
d/dx(x2)+d/dx(2y2)=d/dx(12)
2x+d/dx(2y2)=d/dx(12)
2x+d/dy(2y2)×dy/dx=d/dx(12)
2x+d/dy(2y2)×dy/dx=0
2x+2×d/dy(y2)×dy/dx=0
2x+2×2y×dy/dx=0
2x+4y×dy/dx=0
4y×dy/dx=-2x
dy/dx=-x/2y
Dont understand...What response?How would you this information for your problem?
Look at response 2.
Dont understand...What response?
That response!!↑↑↑As part of the rules of this forum , you are required to post some of your own work.
The slope of the line x+y−2=0 is −1. Where on the ellipse x2+2y2=12 are the tangents −1 ?