Finding generic slope

quasar12

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Jan 17, 2012
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find the generic slope using the limit as h approaches 0 at f(x+h)-f(x)/ h.

f(x)=square root(4x+1), c=2
 
Last edited:
By 'generic slope' I think you mean derivative. This can be a messy problem, algebraically speaking.

\(\displaystyle \displaystyle \lim_{h\to 0} \frac{\sqrt[3]{4(x+h)+1}-\sqrt[3]{4x+1}}{h}\)

Use this fact: \(\displaystyle a-b = (a^{1/3}-b^{1/3})(a^{2/3}+a^{1/3}b^{1/3}+b^{2/3})\)

To get a numerator of \(\displaystyle [(4x+h)+1] - [4x+1]\).
 
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