Q quasar12 New member Joined Jan 17, 2012 Messages 7 Mar 8, 2012 #1 find the generic slope using the limit as h approaches 0 at f(x+h)-f(x)/ h. f(x)=square root(4x+1), c=2 Last edited: Mar 8, 2012
find the generic slope using the limit as h approaches 0 at f(x+h)-f(x)/ h. f(x)=square root(4x+1), c=2
butterfly50 New member Joined Mar 6, 2012 Messages 6 Mar 8, 2012 #4 sorry i dont know im in 5th grade.
D daon2 Full Member Joined Aug 17, 2011 Messages 999 Mar 8, 2012 #5 By 'generic slope' I think you mean derivative. This can be a messy problem, algebraically speaking. \(\displaystyle \displaystyle \lim_{h\to 0} \frac{\sqrt[3]{4(x+h)+1}-\sqrt[3]{4x+1}}{h}\) Use this fact: \(\displaystyle a-b = (a^{1/3}-b^{1/3})(a^{2/3}+a^{1/3}b^{1/3}+b^{2/3})\) To get a numerator of \(\displaystyle [(4x+h)+1] - [4x+1]\).
By 'generic slope' I think you mean derivative. This can be a messy problem, algebraically speaking. \(\displaystyle \displaystyle \lim_{h\to 0} \frac{\sqrt[3]{4(x+h)+1}-\sqrt[3]{4x+1}}{h}\) Use this fact: \(\displaystyle a-b = (a^{1/3}-b^{1/3})(a^{2/3}+a^{1/3}b^{1/3}+b^{2/3})\) To get a numerator of \(\displaystyle [(4x+h)+1] - [4x+1]\).