A similar trick should work also for the second limit.Hi. Try for the first limit, to write it in the form of e^log(something). This change will transform your limit of the form 1^infinite to the indeterminate form 0/0. Then apply L'Hopital's rule. You should get e^2.
Hi,I'm trying to figure it out how to solve this problems. I tried using l'hopital on both but i can't get to solve it.
Please don't give the answers to students, especially when they show no effort at all.Hi. Try for the first limit, to write it in the form of e^log(something). This change will transform your limit of the form 1^infinite to the indeterminate form 0/0. Then apply L'Hopital's rule. You should get e^2.