Mathmasteriw
Junior Member
- Joined
- Oct 22, 2020
- Messages
- 85
A yes apologies for my amature approach to presenting the problem, my bad im new to this advanced stuff.
Heres the question on top of the last photo,
And this is how ive derived it. Any good?
Thank you so much for your time and your knowledge is greatly appreciated Dr.I think what you are saying is that you were given the function [MATH]v = \log_e(2t)[/MATH] and want to find its derivative at [MATH]t = 5[/MATH]. (We say you are "differentiating" it, not "deriving" it; that's an oddity of English math terminology I wish we could fix!)
You evidently have been given a formula that if [MATH]y = A\log_e(x)[/MATH], then [MATH]\frac{dy}{dx} = \frac{A}{x}[/MATH]. (You didn't state what function the formula is meant to apply to, but this is what would fit.)
Applying this formula to your function, taking [MATH]x = 2t[/MATH] and [MATH]A = 1[/MATH], you get [MATH]\frac{dv}{dt} = \frac{1}{2t}[/MATH]. But if so, you forgot to apply the chain rule.
I may be misinterpreting what you intend, because your notation is quite wrong, particularly in writing "=" between a function and its derivative. It will help if you show the actual problem you are working on (even if it's in another language), and the formula(s) you are applying, so we can be sure what you mean.
Jeff, I agree that we want the OP to post the exact problem. As far as 5? goes I suspect it is 5s as in 5 seconds.You are missing the point. We want to see a picture of what was given to you, NOT a picture of what you have written down. It is hard to be sure what you mean. t = 5r? What's r supposed to be? log e is mathematically meaningless. I suspect you mean loge, but I cannot be sure. Is that (2b) or (26)? What you are sending us is a mess. It is not what we want.
Amid the discussion of poor notation, and wanting to see an image of the problem itself as given to you in print, please don't miss the important fact:Thank you so much for your time and your knowledge is greatly appreciated Dr.
I see thanks for those pointers,
Here’s a clearer version of the full question.
Thank you