intercepts

orchidpsycho

New member
was asked to make a table of values and sketch graph for the equation. find x and y intercepts and test for symmetry

y=x^2-3

got the graph with points (0,3) (1,-2) (2,1) (-1,-2) (-2,1) (-3,6) (3,6)

its symmetrical with respect to the y axis because the equation is unchanged when x is replaced with -x

the problem I am wondering is when i find the intercepts I get

y intercept= -3 (0,-3)

but the x I get +- sqrt[3] is that right. wasnt sure how I would present that?

thanks for any help.

soroban

Elite Member
Hello, orchidpsycho!

. . And you noted the symmetry . . . nice touch!

but the x I get +- sqrt[3] is that right. wasnt sure how I would present that?
It's not our fault that the intercepts are irrational numbers . . .
. . . . . . . . . . . . . . . _
We can write: . (±√3, 0)

If you're making a sketch, you can approximate it: .(±1.7, 0) is close enough.

orchidpsycho

New member
thanks.

Thought it was right but up until now I have'nt had any irrational numbers come into play.

Thanks for all the help. I don't know what I would do without people like you to help me along.

One more question. How did you get that square root symbol? Not sure how to do that?

fatsoh

New member
tutorial

Hi there,

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soroban

Elite Member
Hello, orchidpsycho!

How did you get that square root symbol?
There are codes available; I have a partial list.

You precede them with &# (ampersand, 'number') and follow them with ; (semicolon)

√ 8730

θ 952

≠ 8800

± 177

° 176 (degree)

→ 8594