#### orchidpsycho

##### New member

- Joined
- Sep 26, 2005

- Messages
- 41

y=x^2-3

got the graph with points (0,3) (1,-2) (2,1) (-1,-2) (-2,1) (-3,6) (3,6)

its symmetrical with respect to the y axis because the equation is unchanged when x is replaced with -x

the problem I am wondering is when i find the intercepts I get

y intercept= -3 (0,-3)

but the x I get +- sqrt[3] is that right. wasnt sure how I would present that?

thanks for any help.